4x+3y-2x+y 4x-2x+3y+y 2x+4y Taking out 2 common 2(x+2y) Hence the required answer is 2(x+2y)
4
If that was 2x^2 + 5x + 2, it would factor to (2x + 1)(x + 2)
2x+3y=40-2x+2y=20Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.3y=-2xDivide each term in the equation by 3.(3y)/(3)=-(2x)/(3)Simplify the left-hand side of the equation by canceling the common terms.y=-(2x)/(3)if you were solving for x It would be x=-(3y)/2
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
-2x+2
6 + 2x =2(3 + x)
8x-9 -2x plus 11 when solved mathematically is equal to 6x + 2.
2X+6
Subtract 2x from each side: x + 2 = 4Subtract 2 from each side: x = 2
Since y = 2, 2x + 6y is the same as 2x + 12. Because 2x + 12 = 22, 2x = 10. If 2 Xes are equal to ten, then 1 X is equal to 5.
X equals 2 :)
7x = 4x+2x+1xSo 7x/2 = 4x/2 + 2x/2 + x/2 (by the distributive property of division over addition) = 2x + x + x/2
4x+3y-2x+y 4x-2x+3y+y 2x+4y Taking out 2 common 2(x+2y) Hence the required answer is 2(x+2y)
-2x + 6 <= 4x + 18 -2x <= 4x + 12 -12 <= 6x -2 <= x
X + 4(x) + 2x+ 4x + 25x + 2
The variable 'x' would equal (8-y)/2. The variable 'y' would equal 8-2x.