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2x+3y=40-2x+2y=20
Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.
3y=-2x
Divide each term in the equation by 3.
(3y)/(3)=-(2x)/(3)
Simplify the left-hand side of the equation by canceling the common terms.
y=-(2x)/(3)
if you were solving for x It would be x=-(3y)/2
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What does 4x plus 3y-2x plus y equal?
4x+3y-2x+y 4x-2x+3y+y 2x+4y Taking out 2 common 2(x+2y) Hence the required answer is 2(x+2y)
Enter the answer as an ordered pair 2y plus 2x equals 20 y - 2x equals 4?
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
Is point 1 4 on the line represented by the equation x plus 2y equals 5?
The equation "x plus 2y equals 5" is: x + 2y = 5 2y = 5 - x y = 5/2 - 1/2x y = -1/2x + 5/2
What is the y-intercept of 3x plus 2y equals x plus y?
3x + 2y = x + y y = -2x to find y-int set x equal to zero y = -2(0) = 0 or... 3(0) + 2y = (0) + y 2y - y = 0 y = 0 y-intercept is zero
How Do you Solve 2x-3y equals 2 3x plus 2y equals 3?
Given: 2x - 3y = 2 3x + 2y = 3 Take the first equation, and solve for x: x = (2 + 3y) / 2 Now plug it into the second equation: ∴ 3(2 + 3y) / 2 + 2y = 3 ∴ 3 + 9y/2 + 2y = 3 ∴ 9y/2 + 2y = 0 ∴ 22y = 0 ∴ y = 0 Then you can take that value of y, and plug it into either of our first equations to find x; 2x - 3y = 2 ∴ 2x - 3(0) = 2 ∴ 2x = 2 ∴ x = 1 So x is equal to one, and y is equal to zero.
