Best Answer

2x+3y=40-2x+2y=20

Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.

3y=-2x

Divide each term in the equation by 3.

(3y)/(3)=-(2x)/(3)

Simplify the left-hand side of the equation by canceling the common terms.

y=-(2x)/(3)

if you were solving for x It would be x=-(3y)/2

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Q: 2x plus 3y equal 40 -2x plus 2y equal 20?

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4x+3y-2x+y 4x-2x+3y+y 2x+4y Taking out 2 common 2(x+2y) Hence the required answer is 2(x+2y)

2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)

4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80

3x + 2y = x + y y = -2x to find y-int set x equal to zero y = -2(0) = 0 or... 3(0) + 2y = (0) + y 2y - y = 0 y = 0 y-intercept is zero

(2x + 2y) is exactly the same thing as 2(x+y). In order to know how much it actually is, you have to know the numerical values of both 'x' and 'y'.

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