A load that is not sinusoidally varying (i.e. resembling that of a graph of the function sin(x) or cos(x)). This means the load is not cycling or periodic so it does not repeat itself over and over - which is exactly what the graph of the trig function sin(x) demonstrates.
You could try y = 1/sin(x) but I do not see how that helps.
sin and cos functions are complementary..they vary by an angle of 90deg in their graph.. so thts wht i think it is..complementary functions are probably functions whch differ by an angle of 90 i their graph..
the graph of cos(x)=1 when x=0the graph of sin(x)=0 when x=0.But that only tells part of the story. The two graphs are out of sync by pi/2 radians (or 90°; also referred to as 1/4 wavelength or 1/4 cycle). One cycle is 2*pi radians (the distance for the graph to get back where it started and repeat itself.The cosine graph is 'ahead' (leads) of the sine graph by 1/4 cycle. Or you can say that the sine graph lags the cosine graph by 1/4 cycle.
basic algebra, group like terms Sin30-Sin1=Sin(30-2)=Sin(28)
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
It is not possible to draw a graph using this browser.
cos(2x) = 1 - 2(sin(x)^2), so sin(x)^2 = 1/2 - 1/2*cos(2x).
no
The integral of cosine cubed is sinx- 1/3 sin cubed x + c
sin y is a function so the question does not appear to make any sense.
looks like the exponents did not show up, in the first it should be 4 cosine cubed x - 3cosx and the sin 3x should be 3sinx - 4sine cubed x
sin(0) = 0 but, in general, the sine graph need not start at 0. For example, sin(x + 2) does not start at 0.
No.-1
Let y=sin i, x=sin r then y=nx where n is refractive index. A straight line with slope n.
Zack rider
It is zero.