cos(2x) = 1 - 2(sin(x)^2), so sin(x)^2 = 1/2 - 1/2*cos(2x).
It is not possible to draw a graph using this browser.
No.
Yes. Except where sin x = 0, because then you would be dividing by zero so the quotient is undefined.
Do sin(x), square it, and then multiply it by two.
The deriviative of sin2 x + cos2 x is 2 cos x - 2 sin x
Answer 1 Put simply, sine squared is sinX x sinX. However, sine is a function, so the real question must be 'what is sinx squared' or 'what is sin squared x': 'Sin(x) squared' would be sin(x^2), i.e. the 'x' is squared before performing the function sin. 'Sin squared x' would be sin^2(x) i.e. sin squared times sin squared: sin(x) x sin(x). This can also be written as (sinx)^2 but means exactly the same. Answer 2 Sine squared is sin^2(x). If the power was placed like this sin(x)^2, then the X is what is being squared. If it's sin^2(x) it's telling you they want sin(x) times sin(x).
It is not possible to draw a graph using this browser.
Sin squared, cos squared...you removed the x in the equation.
I suggest you use an online graphing calculator to do this. For example, you might try Wolfram Alpha.
no
sin squared
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
Sin^(2)[X] = 1 - Cos^(2)[X] It is based on Pythagorean theorem . Algebraically rearrange Sin^(2)[x] + Cos^(2)[X[ = 1^(2) = 1 Note how it looks like the Pythagorean triangle h^(2) = a^(2) + b^(2) .
No.
sin y is a function so the question does not appear to make any sense.
Multiply both sides by sin(1-cos) and you lose the denominators and get (sin squared) minus 1+cos times 1-cos. Then multiply out (i.e. expand) 1+cos times 1-cos, which will of course give the difference of two squares: 1 - (cos squared). (because the cross terms cancel out.) (This is diff of 2 squares because 1 is the square of 1.) And so you get (sin squared) - (1 - (cos squared)) = (sin squared) + (cos squared) - 1. Then from basic trig we know that (sin squared) + (cos squared) = 1, so this is 0.
The graph of the function y = (sin x)^2 has the same amplitude 1, and the same period 2pi, as the graph of the function y = sin x. The only difference between them is that the part of the graph of y = sin x which is below the x-axis is reflected above x axis. In order to graph the function y = (sin x)^2, we need to find the values of (x, y) for the five key points, where 0 ≤ x ≤ 2pi. Values of (x, y) on y = (sin x)^2: x = 0, y = 0 x = pi/2, y = 1 x = pi, y = 0 x = 3pi/2, y = 1 x = 2pi, y = 0 Plot these five key points and connect them with a smooth curve and graph one complete cycle of the given function.