(X-5)(X+4)=0 so X-5=0 -----X=5 and X=4=0 so X=-4 it factors to (X-5)(X+4) so X=5,-4
5+x=x+5 is an example of the commutative property of addition.
(x + 7)2 = 5 x + 7 = ±√5 x + 7 - 7 = -7 ± √5 x = -7 ± √5
x^(3) + 125 => x^(3) + 5^(3) This factors to (x + 5)(x^(2) - 5x + 5^(2) ) or (x + 5)(x^(2) - 5x + 25) NB The clue is to spot that the constant (125) is a cubic numbers ( 5^(3)). Similarly with other 'cubic factorings'.
If: 2x = x+5 Then: x = 5
It is 200000000000000001000000.
20 sextillion
20 sextillion or 20000 trillion depending on where you are from
this number s pronounced as twenty sextillion
5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 = 78,125
5 to the tenth power would be 5 X 5 X 5 X 5 X 5 X 5 X 5 X 5 X 5 X 5, or 9,765,625.
5 x 5 x 5 x 5 x 5 = 3,125
5x5x5x5x5x5=15,625.
(x-5) is the same as x-5
The twelve is an exponent and the five is the base. All you do is 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 or five multiplied by itself 12 times.
(x^2 - 25)/(x + 5) = [(x - 5)(x + 5)]/(x + 5) = x - 5
Prime factors are 2, 2, 2, 2, 5, 5, 5, 7 Other factors are combinations, i.e. 2 x 2 = 4 2 x 5 = 10 2 x 7 = 14 5 x 5 = 25 5 x 7 = 35 2 x 2 x 2 = 8 2 x 2 x 5 = 20 2 x 2 x 7 = 28 2 x 5 x 5 = 50 2 x 5 x 7 = 70 5 x 5 x 5 = 125 5 x 5 x 7 = 175 2 x 2 x 2 x 2 = 16 2 x 2 x 2 x 5 = 40 2 x 2 x 2 x 7 = 56 2 x 2 x 5 x 5 = 100 2 x 2 x 5 x 7 = 140 2 x 5 x 5 x 5 = 250 2 x 5 x 5 x 7 = 350 5 x 5 x 5 x 7 = 875 2 x 2 x 2 x 2 x 5 = 80 2 x 2 x 2 x 2 x 7 = 112 2 x 2 x 2 x 5 x 5 = 200 2 x 2 x 2 x 5 x 7 = 280 2 x 2 x 5 x 5 x 5 = 500 2 x 2 x 5 x 5 x 7 = 700 2 x 5 x 5 x 5 x 7 = 1,750 2 x 2 x 2 x 2 x 5 x 5 = 400 2 x 2 x 2 x 2 x 5 x 7 = 560 2 x 2 x 2 x 5 x 5 x 5 = 1,000 2 x 2 x 2 x 5 x 5 x 7 = 1,400 2 x 2 x 5 x 5 x 5 x 7 = 3,500 2 x 2 x 2 x 2 x 5 x 5 x 5 = 2,000 2 x 2 x 2 x 2 x 5 x 5 x 7 = 2,800 2 x 2 x 2 x 5 x 5 x 5 x 7 = 7,000