xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
If th equestion meant: (x+y+z)^2The expansion is:(x+y+z)^2= x^2+2xy+y^2+2yz+z^2+2zx
No. 1a and 3d are linear, but 2bc is not. ■
x + y + z = 12 y = 1 x - y - z = 0 Substitute y = 1 in the other two equations: x + 1 + z = 12 so that x + z = 11 and x - 1 - z = 0 so that x - z = 1 Add these two equations: 2x + 0z = 12 which implies that x = 6 and then x + z = 11 gives z = 5 So the solution is (x, y, z) = (6, 1, 5)
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.
-6z + 2 = 3z + 4z + 28 Add 6z to both sides: 2 = 3z + 4z + 28 + 6z = 28 + 13z Subtract 28 from both sides: - 26 = 13z Divide both sides by 13: -2 = z
6z + 28 = 12z + 10 18 = 6z 3 = z
4 x z = 28 z = 28/4 z = 7
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
3x + 2 = 82
z remains undefined.
The solution is (x, y, z) = (2.5, 1, 2.5).
89
6z+28=12z+10 6z-12z=10-28 addition property of equality. -6z=-18 simplification z=3 multiplication property of equality.
4.34684352143
What is the number of integral solution to x plus y plus z equals 100?
It is a linear equation in the variable z.