Set up the equation and solve for z:
28 + z = 56 (next, subtract 28 from each side of the equaition to solve)
z = 28
Chat with our AI personalities
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
If th equestion meant: (x+y+z)^2The expansion is:(x+y+z)^2= x^2+2xy+y^2+2yz+z^2+2zx
No. 1a and 3d are linear, but 2bc is not. ■
x + y + z = 12 y = 1 x - y - z = 0 Substitute y = 1 in the other two equations: x + 1 + z = 12 so that x + z = 11 and x - 1 - z = 0 so that x - z = 1 Add these two equations: 2x + 0z = 12 which implies that x = 6 and then x + z = 11 gives z = 5 So the solution is (x, y, z) = (6, 1, 5)
z=pq