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x + y + z = 12

y = 1

x - y - z = 0

Substitute y = 1 in the other two equations:

x + 1 + z = 12 so that x + z = 11

and

x - 1 - z = 0 so that x - z = 1

Add these two equations: 2x + 0z = 12 which implies that x = 6

and then x + z = 11 gives z = 5

So the solution is (x, y, z) = (6, 1, 5)

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Q: What is the ordered triple of x plus y plus z equals 12 and y equals 1 and x-y-z equals 0?
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