9a + 4a = 26 13a = 26 a = 26/13 a = 2
No answer in integers. Quadratic formula gives roots of x2 + x - 26 = 0 as 5.625 and -4.625
X + 11 = 37. subtract 11 from both sides; X = 37 - 11 = 26.
x2 + 15x = -26x2 + 15x + 26 = -26 + 26x2 + 15x + 26 = 0 where a = 1, b = 15, and c = 26x = [-15 ± √(152 - 4(1)(26))]/2(1)x = (-15 ± √121)/2x = (-15 ± 11)/2x = (-15 + 11)/2 = -4/2 = -2 or x = (-15 - 11)/2 = -26/2 = -13
First rearrange these simultaneous equations in the form of: 7x-4y = 26 5x-4y = 14 Subtract the bottom equation from the top equation remembering that a - - is equal to a plus. So, -4y - - 4y = 0 2x = 12 and therefore it follows that x = 6 Substitute the value of x into the original equations to find the value of y: Therefore: x = 6 and y = 4
26
16
4x = -36 x = -9
15x26=390
How about 20 plus 6 equals 26 as one example
so 26 = 4r so r = 6½
572 Because 2x11=22 and 13x2=26 and 22x26=572.
10 ( x = -3)
26 + 8 = 34
n = 26
40
In base six arithmetic: 16 + 26 + 36 = 106 Another contributor's answer: 3+2+1 = 10