x2 + 15x = -26
x2 + 15x + 26 = -26 + 26
x2 + 15x + 26 = 0 where a = 1, b = 15, and c = 26
x = [-15 ± √(152 - 4(1)(26))]/2(1)
x = (-15 ± √121)/2
x = (-15 ± 11)/2
x = (-15 + 11)/2 = -4/2 = -2 or x = (-15 - 11)/2 = -26/2 = -13
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No answer in integers. Quadratic formula gives roots of x2 + x - 26 = 0 as 5.625 and -4.625
if x2 + 7 = 37, then x2 = 29 and x = ±√29
x = -5 x = 2
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
Draw a circle with its center at the origin and a radius of 3.