x2 + 15x = -26
x2 + 15x + 26 = -26 + 26
x2 + 15x + 26 = 0 where a = 1, b = 15, and c = 26
x = [-15 ± √(152 - 4(1)(26))]/2(1)
x = (-15 ± √121)/2
x = (-15 ± 11)/2
x = (-15 + 11)/2 = -4/2 = -2 or x = (-15 - 11)/2 = -26/2 = -13
No answer in integers. Quadratic formula gives roots of x2 + x - 26 = 0 as 5.625 and -4.625
if x2 + 7 = 37, then x2 = 29 and x = ±√29
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
x = -5 x = 2
Draw a circle with its center at the origin and a radius of 3.
x2+15x+14 = (x+1)(x+14)
You can't factor it
It's an equation. If you want to solve it for x, you can do so as follows: x2 + 15x = 30 x2 + 15x + (15/2)2 = 30 + (15/2)2 (x + 15/2)2 = 30 + 225/2 x + 15/2 = ± √(285/2) x = (-15 ± √570) / 2
572 Because 2x11=22 and 13x2=26 and 22x26=572.
3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.
x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.
(x + 7)(x + 8)
The correct classification of x2 15x is a monomial.
(x-11)(x-4)
(x - 1)(x - 14)
x2 + x2 = 2x2
3x2 - 15x + 42 = 3*(x2 - 5x + 14) which cannot be factorised further.