936
Let f ( x ) = 3 x 5 and g ( x ) = 3 x 2 4 x
x+3=14 x+3-3 = 14-3 (subtract 3 from both sides to solve for x) x = 11
-1
d/dx [f(x) + g(x)] = d/dx [f(x)] + d/dx [g(x)] or f'(x) + g'(x) when x = 3, d/dx [f(x) + g(x)] = f'(3) + g'(3) = 1.1 + 7 = 8.1 d/dx [f(x)*g(x)] = f(x)*d/dx[g(x)] + d/dx[f(x)]*g(x) when x = 3, d/dx [f(x)*g(x)] = f(3)*g'(3) + f'(3)*g(3) = 5*7 + 1.1*(-4) = 35 - 4.4 = 31.1
7
The prime factorization of 312 is 2 X 2 X 2 X 3 X 13In exponential form, 23 x 3 x 132 x 2 x 2 x 3 x 13 = 312
312 = 23 x 3 x 13
2 x 2 x 2 x 3 x 13 = 312 1,2,3,4,6,8,12,13,24,26,39,52,78,104,156,312
104 x 3 = 312
To find the prime factors of 312 start with any factor pair of 312 and keep factoring the composite numbers until all factors are prime. 312 2 x 156 2 x 2 x 78 2 x 2 x 2 x 39 2 x 2 x 2 x 3 x 13 A number of a prime factor of 312 is 2, 3, or 13.
To find what number multiplied by 3 equals 312, you can set up the equation 3x = 312. Dividing both sides by 3 gives you x = 312 / 3, which equals 104. Therefore, 104 multiplied by 3 equals 312.
The prime factorization of 321 is 3 times 107. Write it any way you wish.
lcm(8 12 13) = 312 Using prime factorisation: 8 = 2³ 12 = 2² x 3 13 = 13 lcm = 2³ x 3 x 13 = 312
-3(x+5)+3=12
How about: 24 times 13 = 312 as one example(156,2)(104,3)(78,4)(52,6)(39,8)(26,12)(24,13)
The factors of 312 are 1, 2, 3, 4, 6, 8, 12, 13, 24, 26, 39, 52, 78, 104, 156, 312. For them to be common, they need to be compared to another set of factors. If you meant 3 and 12, the common factors are 1 and 3.
What is the prime factorization of 312. Please tell me don't just gve me an answer that says just joking or something stupid, please with cherry on top!!!!:)