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Find three consecutive odd integers such that the sum of the first twice the second and three times the third is 70?
Let x, x+2 and x+4 be the three consecutive odd integers. x+2(x+2)+3(x+4)=70 x+2x+4+3x+12=70 6x+16=70 6x=54 x=9 The numbers are 9, 11, and 13 Check: 9+2(11)+3(13)= 9+22+39=70
Suppose that y varies directly as the cube of x If x is tripled what is the effect on y?
y will be multiplied by 27. Remember, whatever you do to one side of an equation, you must do to the other. In this case, the relationship between x and y would be expressed as y = x^3 To triple x would look like y = (3x)^3 ...b/c you're tripling the value x alone, not the entire term x^3 y = 27x^3 ...after distributing the exponent (3^3 = 27) In order to set both sides of the equation equal, y must be multiplied by 27... 27y = 27x^3 TADA!
Can you do 3x multiplied by 1?
Absolutely, friend! 3 times 1 is simply 3. Just like painting a happy little tree, sometimes the simplest things can bring the most joy. Keep up the good work!
What does a function multiplied by its inverse equal to?
The identity function.
What does x stand for in the problem 3x equals 96-75?
In 3x = 96 - 75 the "x" stands for the number which, when multiplied by 3, equals the difference between 96 and 75. 96 - 75 = 21 If 3x = 21 then x = 21 divided by 3, or 7
