Let x, x+2 and x+4 be the three consecutive odd integers. x+2(x+2)+3(x+4)=70 x+2x+4+3x+12=70 6x+16=70 6x=54 x=9 The numbers are 9, 11, and 13 Check: 9+2(11)+3(13)= 9+22+39=70
17
yes, if all the data is the same number; when the range is zero. * * * * * That is not true. You need 25% of the values to be small, then 50% identical values, followed by 25% large values. Then the lower (first) quartile will be the same as the upper (third) quartile. The inter-quartile range (IQR) will be zero but the overall range can be as large as you like.
You are supposed to use the chain rule for this. First step: derivative of root of sin2x is (1 / (2 root of sin 2x)) times the derivative of sin 2x. Second step: derivative of sin 2x is cos 2x times the derivative of 2x. Third step: derivative of 2x is 2. Finally, you need to multiply all the parts together.
x^3+y^3 Cube root of the first, x plus cube root of the last, y times What it takes to make the first number, x^2 Opposite sign, - Product of the two cube roots, -xy Then what it takes to make the last. (x+y)(X^2-xy+y^2)
His book Principia Mathematica (1687) has various Lemmas where his invention becomes public. His second and third Lemma is basically Riemann's Sum. If it wasn't for Newton, this would have taken much longer to come about.
-7
10-11-12
18, 20 and 22
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
Their sum is 99.
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
1, 2 and 3 -1, -2, and -3 6 or -6
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
The let statement is: let the smallest of the three integers be x.
n + 2(n+1) + 3(n+2) = 86 n + 2n + 2 + 3n + 6 = 86 6n = 86 - 2 - 6 6n = 78 n = 13 Three consecutive integers are = 13,14,15
121