42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6
Given: 2X + 2Y = 42X + Y = 42/2X + Y = 211 + 20 =212 + 19 =213 + 18 =214 + 17 =215 + 16 =216 + 15 =217 + 14 =218 + 13 =219 + 12 =2110 + 11 =21Given: XY = 1048 x 13 = 104X=8, 13Y=13, 8
It simplifies to: 12x+3y
x=6
11p+11
(y2+13y+22)/(y+2) = (y+11)
-2x+13y=11 13y=2x+11 y=2x/13 + 11/13
If y2 + 13y = 40, then y ~ 15.55If y2 + 13y = 0, then y = -13Improved Answer:-y2+13y+40 = 0(y+5)(y+8) = 0Therefore: y = -5 and y = -8
It can be simplified to: 12x-3w+13y
13y+3z+8
42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6
If you mean: 4y^2 +3 -13y then the expression is (4y-1)(y-3) when factored
(x - 13y)(x + 13y)
Do you mean: y2+13y+40 = 0 If so then when factored: (y+5)(y+8) = 0 Therefore: y = -5 and y = -8.
4y + 3w + 4x + 9y + 7x - 7w (combine like terms)-4w + 11x + 13y
3x - 8y + 2x - 5 - 5y = 5x -13y - 5
a) 4x+13y=40 b) 4x+3y=-40c) multiply b per(-1)=-4x-3y-40d) sum a and c: 4x+13y-4x-3y=40-(-40)=>10y=80 => y=8to find x replace y per its value in a or b and get x=-16