If y2 + 13y = 40, then y ~ 15.55If y2 + 13y = 0, then y = -13Improved Answer:-y2+13y+40 = 0(y+5)(y+8) = 0Therefore: y = -5 and y = -8
x^2+2x+40 = x^2-x+190Subtract x^2 from both sides2x+40 = -x+190Add x to both sides3x + 40 = 190Subtract 40 from each side3x = 150Divide both sides by 3x = 50
10y plus 40 equals 50y.
280
this equals 818
If y2 + 13y = 40, then y ~ 15.55If y2 + 13y = 0, then y = -13Improved Answer:-y2+13y+40 = 0(y+5)(y+8) = 0Therefore: y = -5 and y = -8
a) 4x+13y=40 b) 4x+3y=-40c) multiply b per(-1)=-4x-3y-40d) sum a and c: 4x+13y-4x-3y=40-(-40)=>10y=80 => y=8to find x replace y per its value in a or b and get x=-16
Try elimination.4X + 13Y = 40- 1(4X + 3Y = - 40)4X + 13Y = 40- 4X - 3Y = 40-----------------------add10Y = 80Y = 8-------------find X ( top equation )4X + 13(8) = 404X + 104 = 404X = - 64X = - 16----------------------check in both equations for consistency4(- 16) + 13(8) = 40- 64 + 104 = 4040 = 40-------------top checks4(- 16) + 3(8) = - 40- 64 + 24 = - 40- 40 = - 40-------------------both check and are consistentSo, X is,- 16 ( while Y is 8 )
2 squared plus 2 squared equals 16 because 2 squared is 4 times 4 equals 16. Math: 4x4=16 so your answer is 16 :)!
40
'40 squared' simply means 40 times itself (40 x 40) which equals 1,600
(6, 40) and (-1, 5)
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x^2+2x+40 = x^2-x+190Subtract x^2 from both sides2x+40 = -x+190Add x to both sides3x + 40 = 190Subtract 40 from each side3x = 150Divide both sides by 3x = 50
If x squared = 40 then x = square root of 40 = +/- 6.3255555
120
10y plus 40 equals 50y.