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I'm pretty sure you made some typing mistakes or something when you asked this question, it doesn't look like a usual question. I will solve it anyways though.

Integral of ax^n = (a/n+1)x^(n+1).

In "y", a=1 and n=1.

Putting those values into that magic integrals formula, you get:

(1/2)y^2 + Constant.

So there you go, the integral of "y" is;

0.5y2 + C.

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Q: What is an integral of ydx?
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