the direction of OP is call radial direction of the moving point p while the direction of OQ which is perpendicular to OP in the sense of (theta)angle is called transverse direction of the moving point P.
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If x is a function of time, t, then the second derivative of x, with respect to t, is the acceleration in the x direction.
the left end of the graph is going in a positive direction and the right end is going in a negative direction.
The gradient of a quantity is the greatest rate at which it changes as you move in different directions from where you are now. If the quantity has a negative gradient, that means that the quantity decreases in that direction. A great example of a negative gradient is the elevation of the land at a point on a road that has a hill on one side and a cliff on the other side. The greatest rate at which the elevation changes is in the direction off the edge of the cliff, and it's negative in that direction.
Here is an outline of the solution: Find the velocity of a point on the rim by multiplying the radius times the angular velocity in radians per second (converted from 1 rev per 3 min.). The direction of the rim velocity is tangent to the rim. You have to find the vertical component of this velocity using trig. You find the necessary angle to do this by drawing a radial line to the point on the rim that is 24 m above ground level. There are several parts to this problem, so good luck.
Divide the vector by it's length (magnitude).