x+15=16x=16-15x=1
x2 + 15x = -26x2 + 15x + 26 = -26 + 26x2 + 15x + 26 = 0 where a = 1, b = 15, and c = 26x = [-15 ± √(152 - 4(1)(26))]/2(1)x = (-15 ± √121)/2x = (-15 ± 11)/2x = (-15 + 11)/2 = -4/2 = -2 or x = (-15 - 11)/2 = -26/2 = -13
15x+7y = 4 5x+7y = 2 Subtract the bottom equation from the top equation to eliminate y which will leave you with: 10x = 2 Divide both sides by 10 to find the value of x: x = 2/10 = 1/5 in its lowest terms. Substitute the value of x into the original equations to find the value of y: Therefore: x = 1/5 and y = 1/7
set formula:15x +75 = 6xbring x to left side:15x - 6x + 75 = 09x = - 75x = - 75/9
x=4 y=0
If: 15x = 360 then x equals 360/15 = 24
If you mean: y = -15x+60 then 15x+y = 60 When y = 0 then x = 4 When x = 0 then y = 60 Coordinates of the line are: (4, 0) and (0, 60)
No. An equation must be equal to something, that's why its called an equation. 15x = 60 is an equation, in which case x equals 4
55
x = 4 You have to add the 8x and 7x to get 15x and then divide 60 by 15 to get x by itself.
Here is the answer with Steps: 15x - 18 = -2x - 5 15x = -2x + 13 17x = 13 x = 13/17 x ~ .764705882
9x + 7 = 15x + 1 ___-1_______-1 9x + 6 = 15x -9x_____-9x ____6=6x ____/6_/6 ____1=x x equals 1.
X=-0.6
7
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
OK, SO 15x-3 = 2x+1 15x - 3 + 3 = 2x + 1 + 3 (add three to each side) 15x=2x+4 (simplIfy) 15x-2x=2x-2x+4 (subtract 2x from each side) 13x=4 (simplify) (13x/13)=(4/13) (divide each side by 13) x≈0.30769231
15x = 20y16y = 10z6x = ? Reducing equation #1 says that x = 4/3yDoing the same to #2 says that y = 5/8zIf x=(4/3)y and y=(5/8)z then x must be (4/3)(5/8) = (4/8)(5/3) = (1/2)(5/3) = (5/6)If x=(5/6) then 6x = 5 ■