x+15=16x=16-15x=1
x2 + 15x = -26x2 + 15x + 26 = -26 + 26x2 + 15x + 26 = 0 where a = 1, b = 15, and c = 26x = [-15 ± √(152 - 4(1)(26))]/2(1)x = (-15 ± √121)/2x = (-15 ± 11)/2x = (-15 + 11)/2 = -4/2 = -2 or x = (-15 - 11)/2 = -26/2 = -13
15x+7y = 4 5x+7y = 2 Subtract the bottom equation from the top equation to eliminate y which will leave you with: 10x = 2 Divide both sides by 10 to find the value of x: x = 2/10 = 1/5 in its lowest terms. Substitute the value of x into the original equations to find the value of y: Therefore: x = 1/5 and y = 1/7
set formula:15x +75 = 6xbring x to left side:15x - 6x + 75 = 09x = - 75x = - 75/9
x=4 y=0
If you mean: y = -15x+60 then 15x+y = 60 When y = 0 then x = 4 When x = 0 then y = 60 Coordinates of the line are: (4, 0) and (0, 60)
Oh, dude, so like, if you want to solve for x in the equation 15x = 45, you just divide both sides by 15. So, x would equal 3. But like, who really needs math when you've got comedy, right?
X=-0.6
15x = 20y16y = 10z6x = ? Reducing equation #1 says that x = 4/3yDoing the same to #2 says that y = 5/8zIf x=(4/3)y and y=(5/8)z then x must be (4/3)(5/8) = (4/8)(5/3) = (1/2)(5/3) = (5/6)If x=(5/6) then 6x = 5 ■
f(x)=5x, g(x)=3x-7 gf(x)= = g(f(x)) = g(5x) = 3*(5x) - 7 = 15x-7 So gf(4) = 15*4-7=53
x+15=16x=16-15x=1
-3x + 6 + 15x =11x + 8 ie -3x + 15x - 11x = 8 - 6 ie x = 2
distributive
x2 + 15x = -26x2 + 15x + 26 = -26 + 26x2 + 15x + 26 = 0 where a = 1, b = 15, and c = 26x = [-15 ± √(152 - 4(1)(26))]/2(1)x = (-15 ± √121)/2x = (-15 ± 11)/2x = (-15 + 11)/2 = -4/2 = -2 or x = (-15 - 11)/2 = -26/2 = -13
(x-11)(x-4)
Sounds like a system of equations. Y + 5X = - 2 - 15X - 3Y = 6 substitution using first equation Y + 5X = - 2 Y = - 5X - 2 ==========insert into other equation as this is Y - 15X - 3(- 5X - 2) = 6 - 15X + 15X + 6 = 6 ========================This looks to be a dependent system that has an infinite number of solutions
3(x + 4)(x + 1)