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How can you calculate the arbitrary constant in the solution to an antiderivative?
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A solution for which OH- equals 3.0 x 10 to the negative 10 is classified as an acid basic or neutral and how to calculate?
Base. -log(3.0 X 10^-10) = pH of 9.5
Is 5 1 a solution of y -3x - 2?
I understand the equation to be y = -3x - 2 and the point to be (5,1). I substitute 1 for each appearance of y and 5 for each appearance of x: 1 = -3(5) - 2 = -15 - 2 = -17, which is not a true statement. Therefore, that is not a solution. To get a solution, set x=1, and calculate y by substituting this value (1) for x wherever it appears: y = -3(1) - 2 = -3 - 2 = -5. Therefore, (-5,1) is a solution. (I suspect that this is what you meant to put in the question.)
Is it possible for a sixth-degree polynomial to have only one solution?
Yes. y = x6 has only one solution, at (0, 0).In fact, if you think about it, the family of equations y = a(x+b)6 (where a and b can be any real constant; including x6, 2(x-4)6, 42(x+1)6, and so on) all have one solution. Other than these equations, however, sixth-degree polynomials almost always have multiple solutions or none at all.
What is the solution for 9.4605284 x 1012?
There can be no solution to a number. That is like asking what is the solution to 3!
What is the difference between feasible and optimal solution?
The optimal solution is the best feasible solution
How do you solve g x equals -3x plus 1?
If: x = -3x+1 Then: x+3x = 1 => 4x =1 So: x = 1/4 or 0.25 ----------- I notice that the question requests a solution for g x = -3x + 1. It seems possible that parentheses around the 'x' after the 'g' have gone missing, along with a prime indicating the derivative of the function g. This being the case, we would be seeking the antiderivative of -3x + 1. The antiderivative of a sum is the sum of the antiderivatives. So we can look at -3x and +1 separately. The derivative of x2 is 2x. Therefore, the antiderivative of x is x2/2, and the antiderivative of -3x is -3x2/2. The antiderivative of 1 is x. Overall, the solution is the antiderivative -3x2/2 + x + C, where C is an arbitrary constant.
What is a sentence for Arbitrary?
These are our output. But it is Arbitrary.
Why molarity of a solution remains constant?
Molality of a solution remains constant as mass of a solution independent of temperature.
What is the general solution of a differential equation?
It is the solution of a differential equation without there being any restrictions on the variables (No boundary conditions are given). Presence of arbitrary constants indicates a general solution, the number of arbitrary constants depending on the order of the differential equation.
What is the antiderivative of -cscxcotx?
First, antiderivative = a solution to the indefinite integral therefore to integrate -(csc(x))(cot(x)) first convert it to -cos(x)/sin2(x) To integrate ∫-cos(x)/sin2(x) dx, use substitution u = sin(x) and du/dx = cosx This will make it ∫-1/u2 du and the antiderivative is 1/u +c, therefore the answer is 1/sin(x) + c.
What is ion product constant?
Ion product constant is the product of the concentrations of the ions in a solution at equilibrium. In water, the ion product constant for pure water is Kw = [H3O+][OH-] = 1.0 x 10^-14 at 25°C. It is used to calculate the pH of a solution and can be used to determine if a solution is acidic, neutral, or basic.
What is 21.6g NiSO4 in 1.00 102g H2O assume 100 percent ionization compute the freezing point of this solution?
To determine the freezing point depression of the solution, you first need to calculate the molality of the nickel sulfate (NiSO4) solution. Next, using the molality value and the cryoscopic constant of water, you can calculate the freezing point depression of the solution using the formula: ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the cryoscopic constant of water (1.86°C/kg), and m is the molality of the solution.
Trihydroxybenzoic acid is a not so weak acid with an ionization constant ka equals 0.021 calculate the H plus and the pH of a 0.050 molar solution?
The ionization constant (Ka) for a weak acid can be used to calculate the concentration of H+ ions in solution. Since the acid is triprotic, the Ka value will be used three times to calculate the concentrations of all dissociation steps. The H+ concentration can then be converted to pH using the formula pH = -log[H+].
What is the boiling point of a 2.35 m solution of sodium sulfate?
The boiling point of a solution increases with the concentration of solute particles. To calculate the boiling point elevation, you can use the formula: ΔTb = i * Kf * m, where i is the van't Hoff factor (2 for sodium sulfate), Kf is the ebullioscopic constant, and m is the molality of the solution. If you have these values, you can calculate the boiling point elevation using this formula.
What is a solution that tries to stay at a constant pH?
This solution is called buffered.
what is the molarity of H30?
The molarity of H3O+ (hydronium ion) would depend on the specific solution being referred to, as it is generally formed in acidic solutions. To calculate the molarity of H3O+, you would need to know the concentration of the acid present in the solution and the dissociation constant of the acid.
How much would the freezing point decrease if a 3.23 molal solution were achieved?
The freezing point depression of a solution is given by the equation ΔTf = Kf * m, where ΔTf is the freezing point depression, Kf is the cryoscopic constant, and m is the molality of the solution. With the molality (m) of 3.23 molal and the cryoscopic constant for water (Kf) being approximately 1.86 ºC kg/mol, you can calculate the freezing point depression.
