∫sin2x dx
Use the identity sin2x = ½ - ½(cos2x)
∫[½ - ½(cos2x)] dx = ∫½ dx - ∫½(cos2x) dx
Let's split it up into ∫½ dx and ∫½(cos2x) dx
∫½ dx = x/2 (we'll put the constant in at the end)
∫½(cos2x) dx (Use u substitution with u=2x and du = 2 dx)
∫cosu ¼du = ¼∫cosu du = ¼sinu + c = ¼sin2x (remember to resubstitute)
Subtract the two parts and add a constant
x/2 - ¼(sin2x) + c
This is also equivalent to: ½(x - sinxcosx) + c
Chat with our AI personalities
Answer 1 Put simply, sine squared is sinX x sinX. However, sine is a function, so the real question must be 'what is sinx squared' or 'what is sin squared x': 'Sin(x) squared' would be sin(x^2), i.e. the 'x' is squared before performing the function sin. 'Sin squared x' would be sin^2(x) i.e. sin squared times sin squared: sin(x) x sin(x). This can also be written as (sinx)^2 but means exactly the same. Answer 2 Sine squared is sin^2(x). If the power was placed like this sin(x)^2, then the X is what is being squared. If it's sin^2(x) it's telling you they want sin(x) times sin(x).
The antiderivative of a function which is equal to 0 everywhere is a function equal to 0 everywhere.
(1 - cos(2x))/2, where x is the variable. And/Or, 1 - cos(x)^2, where x is the variable.
The fundamental theorum of calculus states that a definite integral from a to b is equivalent to the antiderivative's expression of b minus the antiderivative expression of a.
-e-x + C.