It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
It's 1/2 of sin(2 theta) .
If r-squared = theta then r = ±sqrt(theta)
If there is a plus in between, that would be equal to 1, as a result of the Pythagorean Theorem. Otherwise, you can convert this into other forms with some of the trigonometric identities for multiplication, but you won't really get it into a simpler form.
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!
1
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
COS squared Theta + SIN squared Theta = 1; where Theta is the angles measurement in degrees.
Cosine squared theta = 1 + Sine squared theta
sin(0)=0 and sin(very large number) is approximately equal to that same very large number.
Tan^2
It's 1/2 of sin(2 theta) .
The derivative of (sin (theta))^.5 is (cos(theta))/(2sin(theta))
If r-squared = theta then r = ±sqrt(theta)