pi/4 radians = 45 degrees. 2pi radians = 360 degrees pi radians = 180 degrees pi/2 radians = 90 degrees pi/4 radians = 45 degrees pi/3 radians = 60 degrees. et seq.,
8
y=3cos(x) peroid is 2pie
3.14
When x = -3
It doesn't exist. The maximum value of the cosine is 1.00, so no angle can have a cosine of (pi), because (pi) is more than 3.
sin pi/2 =1 sin 3 pi/2 is negative 1 ( it is in 3rd quadrant where sin is negative
This is going to require some visualization. Cosine is defined as the x-value on the unit circle. If you picture where a point would be, for example, at the angle of pi/6 (30°) you get a coordinate of (√(3)/2 , 1/2) so cosine is √(3)/2 and sine is 1/2 To find a negative angle you take the reflection across the x-axis. Since this does not chance the x-value, only the y, cosine does not change. The coordinates of -(pi/6) (-30°) are (√(3)/2 , -1/2). cos(-x) = cos(x) sin(-x) = - sin(x)■
0.75
For an angle of 90 or 270 degrees. In radians, pi / 2 and 3 x pi / 2.
In the domain [0, 2*pi],sin is negative for pi < x < 2*picos is negative pi/2 < x < 3*pi/2 andtan is negative for pi/2 < x < pi and 3*pi/2 < x < pi.Also, the same applies for all intervals obtained by adding any integer multiple of 2*pi to the bounds.
-3 -2 -1 -0.5
Negative 3 over 8 simplified is Negative 3 over 8 or negative 0.375
On a Unit Circle, the cosine is the x coordinate of the point on the circle represented by an angle. Angles greater than 90° (pi/2 radians) and less than 270° (3*pi/2 radians) are to the left of the y-axis, so x is negative. Quadrant I is the upper right quadrant (x positive, y positive) 0° < ɵ < 90° Quadrant II is the upper left quadrant (x negative, y positive) 90° < ɵ < 180° Quadrant III is the lower left quadrant (x negative, y negative) 180° < ɵ < 270° Quadrant IV is the lower right quadrant (x positive, y negative) 270° < ɵ < 360°
dhasdhdsad
Let's use these numbers: (There's some rounding and some assumptions here,but these are plenty close enough.)Earth's diameter: 7,926 milesEarth's period of rotation: 24 hoursToronto's north latitude: 43° 40' = 43-2/3 degreesDiameter of the circle that Toronto rotates on = [ 7,926 cosine(43-2/3) ] milesCircumference = pi x diameter = (pi) (7,926) cosine(43-2/3)Speed in miles per hour = circumference / 24 =(pi/24) (7,926) cosine(43-2/3) =750.5 miles (1,207.8 km) per hour
Domain = [0, pi/3) radians or [0, 60) degrees.Range = [-9, 9]