On a Unit Circle, the cosine is the x coordinate of the point on the circle represented by an angle. Angles greater than 90° (pi/2 radians) and less than 270° (3*pi/2 radians) are to the left of the y-axis, so x is negative.
Quadrant I is the upper right quadrant (x positive, y positive) 0° < ɵ < 90°
Quadrant II is the upper left quadrant (x negative, y positive) 90° < ɵ < 180°
Quadrant III is the lower left quadrant (x negative, y negative) 180° < ɵ < 270°
Quadrant IV is the lower right quadrant (x positive, y negative) 270° < ɵ < 360°
The second quadrant (top left).
The third quadrant.
The third (or SouthWest) quadrant.
it is POSITIVE because tangent is said to be as OPPOSITE all over ADJACENT side of the triangle. since the opposite and adjacent sides of theta in Quadrant 3 are both negative, the quotient of two negative integers is POSITIVE. in third quadrant tanƟ= -O/-A
Assuming the question is about negative 145 DEGREES, even though the question does not say so, the answer is the third quadrant.
The second quadrant (top left).
Sine is positive and cosine is negative in the second quadrant of the Cartesian coordinate system. In this quadrant, the angle is between 90 and 180 degrees, where the y-coordinate (sine) is positive and the x-coordinate (cosine) is negative. Thus, for any angle in the second quadrant, sine values are above the x-axis, while cosine values are below it.
It will be in 3rd Quadrant because cosine and sine both are negative in 3rd Quadrant
All the angles in 4th quadrant have positive cosine and negative sine e.g. 280,290,300,310...etc.
The third quadrant.
To find the quadrant and sign of the cotangent function for -495 degrees, first, convert it to a positive angle by adding 360 degrees until the angle is within the standard range. -495 + 720 = 225 degrees. The angle 225 degrees is in the third quadrant, where both sine and cosine are negative, making cotangent (which is the ratio of cosine to sine) positive. Thus, cot(-495 degrees) is positive and located in the third quadrant.
negative negative bottom left
The third (or SouthWest) quadrant.
The coordinates must be as follows: First quadrant: positive, positive Second quadrant: negative, positive Third quadrant: negative, negative Fourth quadrant: positive, negative
The tangent function is equal to the sine divided by the cosine. In quadrant III, both sin and cos are negative - and a negative divided by another negative is positive. Thus it follows that the tangent is positive in QIII.
it is POSITIVE because tangent is said to be as OPPOSITE all over ADJACENT side of the triangle. since the opposite and adjacent sides of theta in Quadrant 3 are both negative, the quotient of two negative integers is POSITIVE. in third quadrant tanƟ= -O/-A
Assuming the question is about negative 145 DEGREES, even though the question does not say so, the answer is the third quadrant.