On a Unit Circle, the cosine is the x coordinate of the point on the circle represented by an angle. Angles greater than 90° (pi/2 radians) and less than 270° (3*pi/2 radians) are to the left of the y-axis, so x is negative.
Quadrant I is the upper right quadrant (x positive, y positive) 0° < ɵ < 90°
Quadrant II is the upper left quadrant (x negative, y positive) 90° < ɵ < 180°
Quadrant III is the lower left quadrant (x negative, y negative) 180° < ɵ < 270°
Quadrant IV is the lower right quadrant (x positive, y negative) 270° < ɵ < 360°
The second quadrant (top left).
The third quadrant.
The third (or SouthWest) quadrant.
Assuming the question is about negative 145 DEGREES, even though the question does not say so, the answer is the third quadrant.
Any ordered pair in the third quadrant has negative x and y values. So (-1,-1), for example, is the third quadrant.
The second quadrant (top left).
It will be in 3rd Quadrant because cosine and sine both are negative in 3rd Quadrant
All the angles in 4th quadrant have positive cosine and negative sine e.g. 280,290,300,310...etc.
The third quadrant.
negative negative bottom left
The third (or SouthWest) quadrant.
The coordinates must be as follows: First quadrant: positive, positive Second quadrant: negative, positive Third quadrant: negative, negative Fourth quadrant: positive, negative
The tangent function is equal to the sine divided by the cosine. In quadrant III, both sin and cos are negative - and a negative divided by another negative is positive. Thus it follows that the tangent is positive in QIII.
Assuming the question is about negative 145 DEGREES, even though the question does not say so, the answer is the third quadrant.
Any ordered pair in the third quadrant has negative x and y values. So (-1,-1), for example, is the third quadrant.
7
y=6x is in the third quadrant while x is negative and in the first quadrant while x is positive.