The derivative of ln(x) is 1/x. Therefore, by Chain Rule, we get:[ln(10x)]' = 1/10x * 10 = 1/xUsing this method, you can also infer that the derivative of ln(Ax) where A is any constant equals 1/x.
If you mean: -10x+4-10x+5 then it is 9-20x when simplified
10x = 9x -25 10x -9x = -25 x = -25
Depends on the value of x if x is 1 then 10x + 20 = 30 if x is 2 then 10x + 20 = 40 if x is 3 then 10x + 20 = 50 if x is 4 then 10x + 20 = 60 if x is 5 then 10x + 20 = 70 if x is 10 then 10x + 20 = 120 And so on
A dot A = A2 do a derivative of both sides derivative (A) dot A + A dot derivative(A) =0 2(derivative (A) dot A)=0 (derivative (A) dot A)=0 A * derivative (A) * cos (theta) =0 => theta =90 A and derivative (A) are perpendicular
The derivative of 10x is 10. This is irrespective of the value of x.
To express the expression 10x - 25y using the greatest common factor, we first need to find the greatest common factor of 10 and 25, which is 5. Next, we can factor out 5 from both terms to get 5(2x - 5y). Therefore, the expression 10x - 25y can be expressed as 5(2x - 5y) using the greatest common factor.
x = 10x, so derivative = 10
No. A quadratic equation always has a second derivative that is a constant. For example -3x2 + 10x - 2 first derivative -6x + 10 second derivative -6
The derivative of ln(x) is 1/x. Therefore, by Chain Rule, we get:[ln(10x)]' = 1/10x * 10 = 1/xUsing this method, you can also infer that the derivative of ln(Ax) where A is any constant equals 1/x.
The LCM of these numbers is 25y. LCM is Least Common Multiple.
2.5
The LCM of 8x and 25y is 200xy
- 5X + 25Y = 0 25Y = 5X Y = (1/5)X ============
4y2 + 25y + 6
25y**8/15y**5 25y**3/15 5y**3/3 (5/3)y**3
15x+25y = 315 25y = -15x+315 y = -0.6x+12.6 which is now in slope-intercept form