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Prove that a constant vector always has a perpendicular derivative?
Wiki User
∙ 13y ago
A dot A = A2
do a derivative of both sides
derivative (A) dot A + A dot derivative(A) =0
2(derivative (A) dot A)=0
(derivative (A) dot A)=0
A * derivative (A) * cos (theta) =0
=> theta =90
A and derivative (A) are perpendicular
Wiki User
∙ 13y ago
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How does calculus help us?
It is used in physics all the time. For example, acceleration is the derivative of velocity which is a derivative of position with respect to time. Calculating the amount of work done in a vector field (like an electrical field) also uses calculus.
Center of curvature in differential calculus?
Center of curvature = r(t) + (1/k)(unit inward Normal) k = curvature Unit inward normal = vector perpendicular to unit tangent r(t) = position vector
How does vector calculus applies to electromagnetism?
Vectors are directional numbers. Calculus determines changes. Electromagnetism involves directional fields and thus vector calculus is the tool to calculate the changes in directional fields.The training in Mathematics and Physics is deficient in that Nature involves the combination of real and vector numbers called Quaternions. Quaternions were invented by William Rowan Hamilton in 1843. Quaternions consist of a real number r and three vectors (i,j,k) such that i2 = j2 = k2 = ijk = -1.A quaternion point is p=r + ix +jy + kz= r + v where v is the vector part.Quaternion calculus has a derivative I call X for Khepra which consists of Hamilton's vector derivative called Del = id/dx + j d/dy + kd/dz and a real derivative d/dr = d/cdt .X= d/dr + Del = d/dr + id/dx + jd/dy + kd/dz = d/cdt + Del = [d/dr,Del]Using this quaternion derivative the fundamental laws of electromagnetism can be derived as th Boundary Condition, 0= XE where E is the quaternion electric field E=Er + Ev = [Er,Ev].The First Derivative of the Electric field isXE= (dEr/cdt - Del.Ev) + (dEv/cdt + DelxEv + Del Er)The Equilibrium Condition for the Electric field occurs when the the First Derivative is set to zero:0=XE= (dBr/dt - Del.Ev) + (dBv/dt + Del Er)This is the Quaternion Equilibrium Condition Equation, notice that the Curl Term DelxEv =0 and is not in the equation. The curl is zero at Equilibrium and the remaining vector terms are "Equal and Opposite"! Equilibrium requires that the sum of the reals and vectors sum to zero. The vectors cannot sum to zero unless DelxEv=0, this happens only when the other terms are parallel or anti-parallel. Equilibrium is the anti-parallel case, thus Newton's "Equal and Opposite" Rule in his 3rd law of Motion.This Equilibrium Condition is the Stationary and Invariant Condition and the Cauchy-Riemann Continutiy Condition.Maxwell's EquationsdBr/dt - Del.Ev=0dBv/dt + DelxEv=0are incorrect in including DelxEv, it should be Del Er. DelxEv is perpendicular to dBv/dt =dEv/cdt. Vector Calculus shows DelxEv is perpendicular to dEv/dr, thus the sum of orthogonal vectors is not zero unless both vectors are zero.This shows that Maxwell's Equations are incorrect and the proper Electromagnetism Equations are derived by Quaternion Calculus.
How can you find a unit vector in the same direction as the given vector?
Divide the vector by it's length (magnitude).
What are the engineering applications of vector calculus?
in which field vector calculus is applied deeply
Prove that if magnitude of vector A is constant then d by dt of vector A is perpendicular to vector A.?
That is not even true!
What is a perpendicular vector?
"Perpendicular " is a relationship, not a vector. Any vector can be perpendicular to any other vector if their angle relationship is an odd multiple of 90 degrees.
Prove that if vector A has constant magnitude then its derivative is perpendicular to vector A?
Suppose A is a vector with real components. A can be written as <f(t), g(t), h(t)>. Since the magnitude of A is constant we have f(t)*f(t) + g(t)*g(t) + h(t)*h(t) = c, where c is a non-negative real number. Take derivative of both sides of equation we get 2*f(t)*df(t)/dt + 2*g(t)*dg(t)/dt + 2*h(t)*dh(t)/dt = 0. Divide both sides by 2, we get f(t)*df(t)/dt + g(t)*dg(t)/dt + h(t)*dh(t)/dt = 0. Thus the dot product of A and its derivative is 0. This implies the angle between A and its derivative is Pi/2. Hence they are perpendicular.
Is zero vector is perpendicular any vector?
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Which are the three vectors that act along the mutually perpendicular direction?
cross product of tow vector result in a vector which is perpendicular the multiplying vector then these three vector are perpedicular
How do you find the component of a vector perpendicular to another vector?
The component of a vector x perpendicular to the vector y is x*y*sin(A) where A is the angle between the two vectors.
A vedtor which is perpendicular to every vector?
The zero vector is not perpendicular to all vectors, but it is orthogonal to all vectors.
Is vector A parallel vector B given that vector A is equal to the zero vector and vector B is equal to the zero vector?
The zero vector is both parallel and perpendicular to any other vector. V.0 = 0 means zero vector is perpendicular to V and Vx0 = 0 means zero vector is parallel to V.
When will be the vector projection and vector components are same?
Ans :The Projections Of A Vector And Vector Components Can Be Equal If And Only If The Axes Are Perpendicular .
Is curl of vector function F must perpendicular to every vector function f?
no!
When sum and difference vector of two vectors are perpendicular .are the vectors too perpendicular?
Yes.
3 types of vector in speed velocity and accelaration?
Position is a vector. Therefore, its first derivative with respect to time (velocity), and its second derivative with respect to time (acceleration) are also vectors.
