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What is the derivative of fx where fx equals 2x-3 all under square root?
Wiki User
∙ 15y ago
f(x) = √(2x -3)
f(x) = (2x - 3)^(1/2)
f'(x) = (1/2)[(2x - 3)^(1/2 - 1)](2)
f'(x) = (2x - 3)^(-1/2)
f'(x) = 1/[(2x - 3)^(1/2)]
f'(x) = 1/√(2x -3)
Wiki User
∙ 15y ago
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