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f(x) = √(2x -3)

f(x) = (2x - 3)^(1/2)

f'(x) = (1/2)[(2x - 3)^(1/2 - 1)](2)

f'(x) = (2x - 3)^(-1/2)

f'(x) = 1/[(2x - 3)^(1/2)]

f'(x) = 1/√(2x -3)

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16y ago

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