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How can you solve the equation x2 plus 3i equals 0?
x2+3i=0 so x2=-3i x=square root of (-3i)=square root (-3)square root (i) =i(square root(3)([1/(square root (2)](1+i) and i(square root(3)([-1/(square root (2)](1+i) You can multiply through by i if you want, but I left it since it shows you where the answer came from. Note: The square root of i is 1/square root 2(1+i) and -1/square root of 2 (1+i) to see this, try and square them!
How do you find zeros of the function f(x) x3 - 2x 21?
That factors to (x + 3)(x^2 - 3x + 7)Setting those equal to zero leaves one real root (-3) and one complex root: one half times (three minus i times the square root of 19) where i is the square root of negative one.
Solve this quadratic equation using the quadratic formula x2 - 6x 6 0?
if this is x squared -6x+6=0 then -6=b, a=1, c=6 6+ square root of -6 squared-4(6x1) - 6+ square root of (36-24) - 6+ square root of 12 - 6+ square root of 4 x square root of 3 - 6 + (2x square root of 3) - that is all divided by 2 multiplied by a meaning it is divided by 2. so x= 6 + or - (2 square root 3) divided by 2 srry steps are jmbled -
How do you simplify square root of x plus 10 plus square root of 10 divided by x algebraically?
simplify the square foor of 49 times x to the third time y to the sixth times the absolute value of z squared
What is the square root of X?
Restricting the discussion to real numbers for now. In this case, the square root is only defined for non-negative numbers; the principal square root of a positive number is the POSITIVE square root. For example, both +5 and -5 are square roots of 25, since both - when squared - give you 25. But the positive square root (+5) is called the principal square root, and if you write the square root symbol, that's the number usually meant.
