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4x-x^2 \ 2-square root 2 multiply 2+squre root x\ 2+squreroot x

= 4x-x^2 (2+squre root x) \ 4_x

= x(4-x) (2+squre root x) \ 4-x

we will cancel the (4-x) so it will be

x(2+squre root x)

= (0) (2+squre root 0) =0

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Q: What is the limit as x approaches 0 of 4x minus x2 divided by 2 minus square root x?
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