2.1673173347
log 1.630 = 0.2122 I just put 1.63 into a calculator, pressed Log, and read the answer to four significant places.
The log(infinity) does not exist. It is impossible to evaluate because infinity is not a number. When evaluating limits infinity is a special case of a nonexistent limit. The limit of the log(x) as x approaches infinity is infinity because log(x) increases without bound when x gets extremely large.
The logarithm of 0.8, written as log(0.8), is approximately -0.09691. This value represents the exponent to which the base (usually 10) must be raised to produce 0.8. Logarithms of numbers between 0 and 1 are negative because they are fractions.
No. The log of a quotient is the log of a denominator subtracted from the log of the numerator.
Use the equation. ln 'x' = log(2) x / log(2) n. '2' being the binary system of 10101010.... However, it may be easier to understand using base '10'. lnx' = log(10)x / log(10)'e' NB This will give a different answer to log base '2' (binary). NNB Within logarithms you can change the base value tp any other base using the above equation. Calculators give logs to base '10'(log) and base 'e' (2.71828.....)(ln). However, you can use any number as a base value e.g. '100' say , or '79' say. providing you use the above eq'n.
First you must decide what base you want to use for the logarithm: base 10, base-e, or some other number. You can calculate logarithms to base 10 or "e" directly on your scientific calculator. Just press 147, followed by "log" (or "ln" for base "e").
The value of log o is penis
determination of log table value
log(21.4) = 1.330413773
log(22) = 1.342422681
log(0.99) = -0.004364805
The numeric value of log(x) is the power you have to raise 10 to in order to get 'x'.
log AB^2 log A+log B+log2
You can, instead, find the log of the ratio. Thus: log(A) - log(B) = log(A/B)
the value of log (log4(log4x)))=1 then x=
log(314.25e) = log10(314.25) + log10e = 2.9316
value of log 0.90