maximum value of 6y+10y
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
60
It is an equation and the value of x works out as 88
-3
It would depend on the feasible region.
maximum value of 6y+10y
42
(6x)(5y)
14
78
Since there is no feasible region defined, there is no answer possible.
It is 18.
The answer depends on the feasible region and there is no information on which to determine that.
2x+2y
If we knew the values of 'x' and 'y', and the boundaries of the feasible region, we could answer that question quickly and easily.
It is 18.