0
y = -6x2 - 12x - 1
We recognize this as the equation of a parabola opening downward, but we don't need to know that in order to answer the question.
At the extremes of a function (local max or min), the first derivative of the function = zero.
The first derivative of the given function with respect to 'x' is dy/dx = -12x -12
Set -12x - 12 = 0.
-x - 1 = 0
x = -1
y = -6x2 - 12x - 1 = -6(1) - 12(-1) - 1 = -6 + 12 - 1 = 5
What else can I help you with?
At the maximum point the value of the second derivative of a function is?
At the maximum point of a function, the value of the second derivative is less than or equal to zero. Specifically, if the second derivative is negative, it indicates that the function is concave down at that point, confirming a local maximum. If the second derivative equals zero, further analysis is needed to determine the nature of the critical point, as it may be an inflection point or a higher-order maximum.
How do you find minimum and maximum value of calculus?
In Calculus, to find the maximum and minimum value, you first take the derivative of the function then find the zeroes or the roots of it. Once you have the roots, you can just simply plug in the x value to the original function where y is the maximum or minimum value. To know if its a maximum or minimum value, simply do your number line to check. the x and y are now your max/min points/ coordinates.
Is the linear equation X equals -14 a function?
No, this is not a function. The graph would have a vertical line at x=-14. Since there are more than one y value for every given x value, the equation does not represent a function. The slope of the equation also does not exist.
What is the output value for y in the y equals 5x plus 3 function when the input value of x equals 2?
y = 5x + 3When x=2,y = 5(2) + 3 = 10 + 3 = 13
What is the range of a a function f when it is defined by f x 2 cos 3 x where x is a real number?
f(x) = 2 cos 3x The amplitude: A = |2| = 2 The maximum value of the function: 2 The minimum value of the function: -2 The range: [-2, 2]
At the maximum point the value of the second derivative of a function is?
At the maximum point of a function, the value of the second derivative is less than or equal to zero. Specifically, if the second derivative is negative, it indicates that the function is concave down at that point, confirming a local maximum. If the second derivative equals zero, further analysis is needed to determine the nature of the critical point, as it may be an inflection point or a higher-order maximum.
What is the maximum value that the graph of ycosx assume?
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
What is the smallest possible value for a where y equals Sin2a reaches its maximum?
The maximum value of the sine function is 1 and that the smallest value for a would be pie divided by 2. So, if 2a= pie divided by 2, then the answer is a=pie divided by 4(simply divide both sides by 2).
What is an extreme value in a set?
the maximum or minimum value of a continuous function on a set.
What are the minimum and maximum values for the objective function C equals 3x plus y?
The answer will depend on the ranges for x and y. If the ranges are not restricted, then C can have any value.
What is the maximum function value of f(x)-(x-3)2?
The question is not clear. A function is defined by an equation and that requires an equals sign. there is no equals sign in the question. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals".
The function y equals sin θ is not a function beacause sin 30 equals sin 150?
Y=sin X is a function because for each value of X, there is exactly one Y value.
Is a function that is continuous over a finite closed interval not have a maximum or a minimum value over that interval?
A function that is continuous over a finite closed interval must have both a maximum and a minimum value on that interval, according to the Extreme Value Theorem. This theorem states that if a function is continuous on a closed interval ([a, b]), then it attains its maximum and minimum values at least once within that interval. Therefore, it is impossible for a continuous function on a finite closed interval to not have a maximum or minimum value.
How do you find minimum and maximum value of calculus?
In Calculus, to find the maximum and minimum value, you first take the derivative of the function then find the zeroes or the roots of it. Once you have the roots, you can just simply plug in the x value to the original function where y is the maximum or minimum value. To know if its a maximum or minimum value, simply do your number line to check. the x and y are now your max/min points/ coordinates.
What is the maximum value of y equals -x2-x plus 6?
8
What is the value of unit step function at t equals 0?
The unit step function at t=0 is defined to have a value of 1.
What is the approximate value of the function at x equals 5?
To provide an approximate value of the function at ( x = 5 ), I would need the specific function or context you're referring to. If you can provide the equation or details about the function, I can help you calculate or estimate the value.
