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y = -6x2 - 12x - 1

We recognize this as the equation of a parabola opening downward, but we don't need to know that in order to answer the question.

At the extremes of a function (local max or min), the first derivative of the function = zero.

The first derivative of the given function with respect to 'x' is dy/dx = -12x -12

Set -12x - 12 = 0.

-x - 1 = 0

x = -1

y = -6x2 - 12x - 1 = -6(1) - 12(-1) - 1 = -6 + 12 - 1 = 5

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Q: What is the maximum value of the function y equals -6x2-12x-1?
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