The domain of y = x0.5 is [0,+Infinity]. There are no X and Y intercepts for this function.
Not asked, but answered for completeness sake, the range is also [0,+Infinity]. That is why there are no intercepts.
Taken one step further, if you include the domain [-Infinity,0) in your analysis, you must include the imaginary range (i0,iInfinity] in your result set.
domain is set of real numbers range is set of real numbers
5
In the complex field, the domain and range are both the whole of the complex field.If restricted to real numbers, the domain is x >= 4 and y can be all real numbers >= 0 or all real numbers <= 0 [or some zigzagging pattern of that set].
A line intercepts the y axis when x=0. If we put x=0 into the equation we get 2x0 + 6y = 36 6y = 36 y = 6 (dividing both sides by 6) Thus the line intercepts the y axis when x is 0 and y is 6. This is the point with the coordinates (0,6)
Y = 3x - 2This is the equation of a straight line that intercepts the Y axis at -2. It has a gradient of 3/1, meaning that for every unit moved to the right, the line rises three units up the y axis.
The 'x' and 'y' intercepts of that equation are both at the origin.
Because when your solving a quadratic equation your looking for x-intercepts which is where why equals 0 and x equals what ever the answer is.
If the equation is 7x - 3y = 21 then (3, 0) and (0, -7).
x = ±2
The domain and range are both [-6, +6].
x=3 y=2 z=6
The equation is equal to y = x-4. It has an infinite number of points. The intercepts are (4, 0) and (0, -4)
type you answer here!
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
y= mx + b. M is the slope of the line, when b is where the line intercepts the y axis.
The equation 9=3y has the x-intercept (0,0) and the y-intercept (0,3).