5
domain is set of real numbers range is set of real numbers
The domain of y = x0.5 is [0,+Infinity]. There are no X and Y intercepts for this function.Not asked, but answered for completeness sake, the range is also [0,+Infinity]. That is why there are no intercepts.Taken one step further, if you include the domain [-Infinity,0) in your analysis, you must include the imaginary range (i0,iInfinity] in your result set.
x = the domain y = the co-domain and range is the output or something e_e
The domain is any subset of the real numbers that you choose, The range is the set of all values that the points in the domain are mapped to.
The domain of the function f(x) = (x + 2)^-1 is whatever you choose it to be, except that the point x = -2 must be excluded. If the domain comes up to, or straddles the point x = -2 then that is the equation of the vertical asymptote. However, if you choose to define the domain as x > 0 (in R), then there is no vertical asymptote.
The domain is (-infinity, infinity) The range is (-3, infinity) and the asymptote is y = -3
This is the equation of a line with slope -4 and y intercept at 0. The domain is all real numbers as is the range.
Domain and range are not sufficient to determine the y intercept. For example, the domain and range for the straight line y = 2x + 3 are the whole of the real numbers. That tells you nothing about the intercept.
Most equations WILL have a y-intercept. However, it is possible to have an equation without one! One way is to limit the domain, or how far the x goes. Another way is to make it so that the function is a line that goes straight down. The line would obviously be a bit left or right from the center.
Domain is the independent variable in an equation. It is what you put "in" the equation to get the Range.
First, you have to have domain and range, a graph, or an equation in slope-intercept form ( y=mx + b) to determine if an equation is a function. The slope intercept form here is Y=3/1x + 1. So Yes, this equation is a function. If you want to know how to convert into y=mx + b form, ask how to do it here, or look it up on the internet. Hope I helped :-)
The set of all values of x, for which the equation is true is the domain of the function defined by that equation.
The domain is the (x) of the equation, and if (x) is zero then that is the domain. So yes the domain can be zero.
No equation can have that property. It cannot be an equation if it is not true. If necessary, the domain must be amended. An equation can have different forms over different parts of its domain.
Differential equation is defined in the domain except at few points (may be consider the time domain ti ) may be (finite or countable) in the domain and a function or difference equation is defined at each ti in the domain. So, differential equation with the impulsive effects we call it as impulsive differential equation (IDE). The solutions of the differential equation is continuous in the domain. But the solutions of the IDE are piecewise continuous in the domain. This is due to the nature of impulsive system. Generally IDE have first order discontinuity. There are so many applications for IDE in practical life.
Differential equation is defined in the domain except at few points (may be consider the time domain ti ) may be (finite or countable) in the domain and a function or difference equation is defined at each ti in the domain. So, differential equation with the impulsive effects we call it as impulsive differential equation (IDE). The solutions of the differential equation is continuous in the domain. But the solutions of the IDE are piecewise continuous in the domain. This is due to the nature of impulsive system. Generally IDE have first order discontinuity. There are so many applications for IDE in practical life.