X2 - 12X = 8 X2 - 12X - 8 = 0 Looks like a job for the quadratic formula. X = - b (+/-) sqrt(b2 - 4ac)/2a a = 1 b = -12 c = - 8 X = - (- 12) (+/-) sqrt[(- 12)2 - 4(1)(- 8)]/2(1) X = 12 (+/-) sqrt(144 + 32)/2 X = 12 (+/-) sqrt(176)/2 X = [12 (+/-) 4sqrt(11)]/2 =======================exact answer, less factor elimination. you do approximation.
x - 8 = 17x = 25 (add 8 to both sides)
x2 + 6x = 16x2 + 6x - 16 = 0(x + 8)(x - 2) = 0x + 8 = 0 or x - 2 = 0x = -8 or x = 2Since it is given that x > 0, then x = -8 is not a solution of the equation. Thus, the only solution is x = 2.
y = cx when x = 8, y = 12 so that 12 = 8c which gives c = 12/8 = 1.5
Of course, x-1=8 is a solution. Any equation which results with the variable value as 9 is ur answer. For eg: x = 9 / x-9 = 0 1 - x = -8 / x-1 = 8 x-2 = 7 / 2-x = -7 Any, any such equation will be your answer(correct answer). Enjoy
If x = 8 satisfies the equation 19 - x = 12, then it is a solution of the equation. 19 - x = 12 19 - 8 = ? 12 11 ≠ 12 Since x = 8 does not satisfy the equation, x = 8 it is not a solution.
If you mean: y = -8 and y = -2x-12 then the solution is x = -2 and y = -8
6 and 14 Solution x - y= 8, so x =8 + y, (x + y)/2 = 10, x + y = 20, Substituting x = 8 + y, we have: 2 y + 8 = 20, or 2y = 12, y = 6, x = 6+8= 14
x - 8 = 12 x - 8 + 8 = 12 + 8 x = 20
x = 12 and y = 8
To solve the equation 2X+8=X+10 the first step is to get all instances of the variable 'X' on the same side of the 'equals' sign. To do this, we must first subtract 'X' from both sides of the equation: 2X+8-X=X+10-X which then becomes X+8=10. The next step is to leave the variable 'X' alone on it's side of the 'equals' by subtracting the numeral 8 from both sides of the equation: X+8-8=10-8 which then becomes X=2. To confirm that the solution is correct, we then substitute the solution we arrived at into the original equation in place of the variable 'X': 2*2+8=2+10 2*2=4 so: 4+8=2+10 4+8=12 and 2+10=12 so the final solution is: 12=12 Therefore the answer to the question "Is 2X+8 equal to X+10" is Yes, and the value of the variable 'X' is 2
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
the solution is the answer to the equation. A solution is any value that makes the equation true. x + 2 = 10 has exactly one solution ....x=8 x + 2 > 10 has infinitely many solutions....x=9 or 10 or 11 or 12 or 13, etc
Example:- What are the dimensions of a rectangle when its length is greater than its width by 4 cm and has an area of 96 square cm? Let the length be x+4 and the width x: length*width = area (x+4)*x = 96 => x2+4x-96 = 0 => (x+12)(x-8) = 0 when factored So: x = -12 or x = 8 the dimensions can't be negative Solution: length = 12 cm and width = 8 cm Check: 12*8 = 96 square cm
"-X-8-X-4" cannot be solved. This is because it is an expression, and expressions can only be reduced into another expression, not solved. In this example, it would reduce to "-2X-12". However, if you substitute -4 for X, you get -4. If the problem read "-X-8-X-4=-4", -4 would be an appropriate solution for X.
-8
X2 - 12X = 8 X2 - 12X - 8 = 0 Looks like a job for the quadratic formula. X = - b (+/-) sqrt(b2 - 4ac)/2a a = 1 b = -12 c = - 8 X = - (- 12) (+/-) sqrt[(- 12)2 - 4(1)(- 8)]/2(1) X = 12 (+/-) sqrt(144 + 32)/2 X = 12 (+/-) sqrt(176)/2 X = [12 (+/-) 4sqrt(11)]/2 =======================exact answer, less factor elimination. you do approximation.