(x3-3x2+6x+5)/(x-2) = x2-x+4 remainder 13 or as x2-x+4+13/(x-2)
It's difficult to show the workings out on this computer but division in algebra has a lot in common when doing long division with integers.
Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
- ln ((x^2)-4)
-15
Your answer will depend on the parameters of the instructions. If you're looking for the first derivative, simply use the product rule by changing the denominator to a negative exponent and bringing it up (take the negative square root of the quantity x-2 to the top). Then, follow the rules of calculus and algebra. Wow, that's a mess. Let's see... you get "the quantity x cubed plus 6x squared plus 3x plus 1 times the quantity -1(x-2) raised to the negative second plus the quantity x-2 raised to the negative first times the quantity 3x squared plus 12x plus 3." This is because of the Product Rule. Simplifying (by factoring out (x-2) raised to the negative second and combining like terms) gives us "(x-2) raised to the negative second times the quantity 2x cubed minus 24x minus 7." This can also be written as "2x cubed minus 24x minus 7 all over the quantity x-2 squared." f'(x)= 2x^3-24x-7 (x-2)^2
sin squared
24
9 minus 8
000000
-116
You have to put your heart into it!
How about: (3 squared minus 2 cubed) + 1 to the fourth 3 cubed minus 5 squared log 100 Kim Basinger's weeks minus Doris Day's cents.
3x3x3+3/3
964 = 1,000 - 36
2x(x−6)(x+1)
4a3 - 4a2 = 4a2*(a - 1)
(a - 2)(a^2 + 6)
x(x + 3)(x - 4)