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The square root of 3 is 1.73205081* * * * *or -1.732050812.23606798
3x2 = 27Divide each side by 3:x2 = 9Take the square root of each side:x = + 9x = - 9
You add 16. Why? Because 16 is the square of half the co-efficient of x.That's the rule you use, to get the square of x + 4.Completing the square is useful for solving for x, as the following shows:x2 + 8x = 11 : givenx2 + 8x + 16 = 27 : add 16 to both sidesx + 4 = ±√27 = ±3√3 : square-root of both sidesx = ±3√3 - 4 : subtract 4 from both sides(Note, the rule works only when x2 has no express co-efficient.)
commutative property
8x + 33 = 7x + 27 Subtract 7x from both sides: x + 33 = 27 Subtract 33 from both sides: x = -6