If: 3x+y = 4 and x+y = 0 Then: x = 2 and y = -2
Let's simplify: f(x) = 3x-3x, so f(x) =0, so y=0 The graph is a line along the x-axis.
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
x = 1, y = 0
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
If 3X-27= 0 then X=9
6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6
3x + 2 = 0 3x = -2 x = -2/3
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
Slope=3, y-intercept=0. y=3x or y=3x+0
3x + 8 = 8 Therefore, 3x = 0 x = 0/3 x = 0
0
the answer is -3x = 0
x = 0
3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
3x - y = -4 3x - y = 0 Those lines do not intersect. They are parallel. You can demonstrate by solving either of them for one of the two variables, then plugging it's value into the other: 3x - y = -4 ∴y = 3x + 4 Now substitute: 3x - y = 0 ∴ 3x - (3x + 4) = 0 ∴ 3x - 3x - 4 = 0 ∴ -4 = 0 This result is obviously incorrect, indicating that the lines do not intersect.
y = -1x/2 3x + 6y = 0 -3x -3x __________ 6y = 0 - 3x --- -------- 6 6 y= -3x/6 y= -1x/2