x = 7
X = 81 sqrt(X) + 3 = 12 ( subtract 3 from each side ) sqrt(X) = 9 (square both sides ) X = 81 ( the square root of 81 is 9 )
Square root of x = 29 can be rearranged by squaring both sides of the equation. That would leave you with: x = 29^2 (or 29 squared) So, work out what 29 squared is and that's what x is equal to.
If x squared equals n, then x is the square root of n.
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)
Yes, because when x equals 1, the square root of x is rational and the square root of -x is irrational, and when x equals -1, the square root of x is irrational and the square root of -x is rational.
2x2+9 = -412x2 = -41-92x2 = -50x2 = -25x = -5Check: (2*-52)+9 = -41Sorry, you can't have -5 as square root of -25.x = 5i, where i is the imaginary square root of -1
If x equals the square root of ...., then you already have solved for x
x^2 + 12x = 5 x^2 + 12x + __ = 5 + __ x^2 + 12x + 36 = 5 + 36 (The 36 I got from taking half of 12 and then squaring that number (which is 6).) (x + 6)^2 = 41 x + 6 = (the square root of 41) x = (the square root of 41) - 6. Hope that helped :)
The square root of a value v is a number x such that, x multiplied by x equals v. Note that -x is also a square root.
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.
x=square root (-2) =i(square root of 2)WHERE i2 =-1
x = 9
x = 8
No. The Square root of x is not the value of x. So it can not be simplified beyond: Root X + root 3x Yes. The square root of 3x equals the square root of 3 times the square root of x, so when you add another square root of x, you can factor out the square root of x, thereby simplifying the expression to the square root of x times the sum of one plus the square root of three.
Yes, if x and y = 1 √1 + √1 = √1 + 1 1 + 1 = 1 + 1 QED
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