x = 41
√x = √41 √x ≈ 6.4
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x = 7
X = 81 sqrt(X) + 3 = 12 ( subtract 3 from each side ) sqrt(X) = 9 (square both sides ) X = 81 ( the square root of 81 is 9 )
Square root of x = 29 can be rearranged by squaring both sides of the equation. That would leave you with: x = 29^2 (or 29 squared) So, work out what 29 squared is and that's what x is equal to.
If x squared equals n, then x is the square root of n.
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)