x = 8
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x2 + 8x + 5 = 0 is an expression, not a value, and thus does not actually have a square root. If you are looking to solve for x, then you can say: x2 + 8x + 5 = 0 ∴ x2 + 8x + 16 = 11 ∴ (x + 4)2 = 11 ∴ x + 4 = ±√11 ∴ x = 4 ±√11
Yes, because when x equals 1, the square root of x is rational and the square root of -x is irrational, and when x equals -1, the square root of x is irrational and the square root of -x is rational.
The square root of a value v is a number x such that, x multiplied by x equals v. Note that -x is also a square root.
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.