Well, darling, the square root of x to the fourth power is simply x squared. It's like asking how many slices of cheesecake you can fit in your mouth at once - the answer is two, unless you're feeling extra ambitious. Just remember, math may be complex, but dessert is always a simple pleasure.
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Oh, dude, the square root of x to the fourth power is just x squared. It's like, you take the square root of x squared, which is x, and then square it again, and boom, you're back to x squared. Easy peasy lemon squeezy.
Ah, what a happy little question we have here! When you have x to the fourth power and you take the square root of it, you'll get x squared. Just like painting, math can be a beautiful and calming experience when you take it step by step. So go ahead and embrace the joy of simplifying those exponents!
By radical, I am assuming that you mean square root, not cube root, quartic root, or otherwise. If this is the case, then we can use fractional exponents to help. Change sqrt(x) to x^(1/2), or x to the one half power. Then we take a radical of a radical which becomes sqrt(x^(1/2)) = (x^(1/2))^(1/2) = x^(1/4). When we raise a power to a power, we multiply exponents. So the answer to the square root of the square root of x is x to the one fourth power, or the 4th root of x.
It is x*sqrt(x) or x^(3/2)
Use the power rule: It should equal (sqrt(x))*x^((sqrt(x))-1). You may, however, wish to double check your answer.
To simplify x divided by the square root of x, we can rewrite the square root of x as x^(1/2). Dividing x by x^(1/2) is equivalent to multiplying x by x^(-1/2), which simplifies to x^(1-1/2). Therefore, x divided by the square root of x simplifies to x^(1/2), which is the square root of x.
There is no answer to this problem unless x is 0. For the suare root of 98x to be a real number, x has to be positive or zero. For the square root of -147x to be a real number, x has to be negative or zero. Seeing has x has to fit both requirements, the problem has an answer only if x is zero.