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What is the second derivative of square root x?
It is negative one divided by 4 multiplied by x to the power of 1.5 -1/(4(x^1.5))
What is the derivative of square root of x?
sqrt(x) = x^(1/2) The derivative is (1 / 2) * x^(-1 / 2) = 1 / (2 * x^(1 / 2)) = 1 / (2 * sqrt(x))
What is the derivative of y equals square root of 8x plus square root of 4x?
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)
How do solve a composite function that is a radical inside of a radical?
By radical, I am assuming that you mean square root, not cube root, quartic root, or otherwise. If this is the case, then we can use fractional exponents to help. Change sqrt(x) to x^(1/2), or x to the one half power. Then we take a radical of a radical which becomes sqrt(x^(1/2)) = (x^(1/2))^(1/2) = x^(1/4). When we raise a power to a power, we multiply exponents. So the answer to the square root of the square root of x is x to the one fourth power, or the 4th root of x.
What is the square root of x to the power of 3 equal to?
It is x*sqrt(x) or x^(3/2)
