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Using logs. to base '10'.

Then

log(10)50 = 1.698970004.....

However, using the 'natural' base 'ln'.

ln(e) 50 = 3.912023005.....

Log bases are interchangeable using the equation.

log(10)e = ln(e)e / ln(e)10

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lenpollock

Lvl 16
2mo ago

What else can I help you with?