linear
(a + 2b)(a + 2b)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
The only factor is 2. 2*(t3 + 2t2 + 4x)
Two is a prime factor of that equation.
4
ab2
√(ab2) = (√a)*b
(a -b) · (a2+ab+b2) = (a3+a2b+ab2) - (a2b+ab2+b3) = a3 -b3 (a+b) · (a2 -ab+b2) = (a3 -a2b+ab2) +(a2b -ab2+b3) = a3+b3 More generally: (a ∓ b) · (an-1 ±an-2b +an-3b2 ±an-4b3 +±...+a(±b)n-2 +(±b)n-1) = an ± bn. The mixed terms cancel out themselves.
y(a - by^3 + x) a(b + 3)(b - 5)
AB2
The GCF is ab2
Factor by grouping. x2y - xyb - abx + ab2 The first two can factor out an xy, so xy(x - b) The second two can factor out a -ab, so -ab(x - b) and we have xy(x - b) - ab(x - b) Since what is inside the parentheses is alike, we can be assured that we have factored correctly and now continue to group: ANS: (x - b)(xy - ab)
In the graphical method using the Gibbs adsorption isotherm equation, the surface excess concentration of AB2 can be obtained by plotting the surface excess Gibbs free energy against the bulk concentration of AB2 at equilibrium. The intercept of the linear plot on the y-axis gives the surface excess concentration of AB2 at the surface. This method helps quantify the extent of the surface concentration of AB2 in the system.
Let consider the right triangle ABC with hypotenuse AB and heigth AC then base is BC Pythagorean theorem states that AB2=AC2+BC2 so BC2=AB2-AC2 then BC=sqrt(AB2-AC2)
linear
5m