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You need to solve the equation:log3(x-1) = 0

Taking antilogarithms (base 3) on both sides, you get:

3^log3(x-1) = 3^0

x-1 = 1

x = 2

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6y ago
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6y ago

It is x = 4.

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Q: What is the zero of the logarithmic function f(x) log3 (x-1)?
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