You need to solve the equation:log3(x-1) = 0
Taking antilogarithms (base 3) on both sides, you get:
3^log3(x-1) = 3^0
x-1 = 1
x = 2
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(x - 7)(x - 1) or (x + 7)(x + 1) depending on sign of 8x so zero is +/- 7 and +/- 1
29
true
a constant
Assume you want to know what is the formula of the gradient of the function in multivariable calculus. Let F be a scalar field function in n-dimension. Then, the gradient of a function is: ∇F = <fx1 , fx2, ... , fxn> In the 3-dimensional Cartesian space: ∇F = <fx, fy, fz>