0
Add your answer:
Earn +20 pts
How do you Solve the formula y equals mx plus b for M?
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
What does the b mean in y equals mx plus b?
If the equation Y = mX + b is graphed on standard Cartesian orthogonal x-y coordinates, then: -- the graph is a straight line -- 'm' is the slope of the line -- 'b' is the Y-intercept, i.e. the number where the line crosses the Y-axis, i.e. the value of 'Y' when X = 0 .
What is c in y equals mx plus c?
It is the intercept: the value that y takes when x = 0
What is the slope of the equation x plus 2y equals -10?
-8
X squared plus 16x plus a equals parenthesis x plus b parenthesis squared In the equation above a and b are constants if the equation is true for all value of x what is the value of a?
a=64 b=8 (x+16x+64)=(x+8)^2
Is y equals mx plus b different from f x equals mx plus b?
yes
Y equals mx plus b for x?
x = (y-b)/m
How do you Solve the formula y equals mx plus b for M?
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
What is 2x-2y equals -10 in y equals mx plus b form?
It is: y = x+5 in y = mx+b form
Y equals mx plus b solve for m?
y-b/x=m
How do you solve for y in the equation y equals mx plus b?
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
What if you have the equation of y-1 equals x and you want it to b in y equals mx plus b?
the y-1 is a minus .
Why is b the y-intercept in y equals mx plus b?
If x=0, then y=b on the vertical line at x=0.
What does x equal with y equals mx plus b?
In the equation y = mx + b, x is the independent variable.Also, m is the slope, b is the y-intercept, and y is the dependent variable.
What is the x intercept in the equation y equals mx plus b?
y = mx + bAt the x-intercept, y = 0 :0 = mx + bSubtract b from each side of the equation :-b = mxDivide each side by 'm' :-b/m = x
What is y-6x equals 15-x in y equals mx plus b form?
It is: y = 5x+15
In the equation for a straight line y equals mx plus b what is the x-intercept equal to?
The x-intercept is equal to -b/m.
