It is a quadratic equation with one unknown variable, x which has no real roots.
2(x - 7)(x - 1)
It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
x= Negative 4
X=7
x2 + 2x - 15 = 0(x + 5) (x - 3) = 0x = -5x = +3
3x2 + 2x - 8 = 0 is a quadratic equation.
-x2+2x
7x2 -4x -5x2 +2x = 2x2 -2x
No
2x2 + 2x - 8 = 2(x2 + x - 4). This can take any value greater than or equal to -8.5
2x squared minus 4
5x lolzz 8)
(2x - 3)(x + 2)
(x - 1)(2x - 9)
(x - 2)(2x + 7)
(2x-3)(x-1)
(2x - 3)(x + 2)