It is a quadratic equation with one unknown variable, x which has no real roots.
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2(x - 7)(x - 1)
It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
x= Negative 4
X=7
x2 + 2x - 15 = 0(x + 5) (x - 3) = 0x = -5x = +3