Solve for Y algebraically. 4X + 8Y = 16 8Y = - 4X + 16 Y = - 1/2X + 2 graph and see that the Y intercept = 2
(A): 4x + y = 7 (B): 2x - 3y = -7 2*(B) 4x - 6y = -14 Subtract from (A) 7y = 21 Divide both sides by 7: y = 3 Substitute in (A): 4x + 3 = 7 ie 4x = 4 or x = 1 Answer: x = 1 , y = 3
A graph that has 1 parabolla that has a minimum and 1 positive line.
Yes.
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)
2
x-intercept of y equals -4x plus 4 y = -4x + 4 0 = -4x + 4 -4 = -4x 1 = x So 1 is the x-intercept
(2, 7)
when x = -0.25
(1,-2)
y = 4x-3
4x+4y=16 y=5 4x+ 20=16 4x=-4 x=-1
(2, 1)
y = -4x + 4 x intercept is where y = 0 0 = -4x +4 4x = 4 x = 1
It is: y = -4x+12
So substitute for y : x + 4x = 5 so 5x = 5, so x=1, y=4
Parallel, the slope of the second equation is 4