y = 4x-3
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Yes. Think of y as being a function of x. y = f(x) = x2 + 1
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
(the shape is an upside down 'u').
y = x2 - 4x + 4 can be factored into y = (x-2)(x-2) The repeated factor is 2.
When x = -5