What value of A satisfies the equation 2sinA-1 equals 0?

Answer 1

2sinA - 1 = 0

2sinA = 1

sinA = 0.5

so A = sin-1(0.5) and

so A = pi/6 + 2n*pi radians

or A = 5pi/6 + 2n*pi radians

for all integer values of n.

Equivalently,

A = 30 + 360n degrees

or 150 + 360n degrees for all integer values of n.