2x-y=4
Generally, function values are Y values, so.......... 6X + 2Y = 24 subtract 6X from each side 2Y = - 6X + 24 divide both the integers on the right by 2 Y = - 3X + 12 -------------------------the function
6x+2y-3 = 0 2y = -6x+3 y = -3x+3/2 in slope intercept form
Perpendiculat straight lines.
2p = 4y - 12xy - 6x, 3q = 12 - 15y so 2p - 3q = 4y - 12xy - 6x - (12 - 15y) = 4y - 12xy - 6x - 12 + 15y = 19y -12xy - 6x - 12
-6x = 2y - 120 -2y -2y -2y - 6x = -120 +6x +6x -2y = 6x - 120 -2y/-2 = 6x/-2 - 120/-2 y = -3x + 60
perpendicular
2x-y=4
Generally, function values are Y values, so.......... 6X + 2Y = 24 subtract 6X from each side 2Y = - 6X + 24 divide both the integers on the right by 2 Y = - 3X + 12 -------------------------the function
6x+2y-3 = 0 2y = -6x+3 y = -3x+3/2 in slope intercept form
Perpendiculat straight lines.
(x, y) = (3, 7) is a solution.
6x+2y=4 gives y=2-(1/3)x
2y = 6x - 8y = 3x - 4========m(slope) = 3=========
x = 3y - 3 so 6 (3y - 3) + 2y = -12 ie 18y - 18 + 2y = -12 ie 20y = 6 so y = 0.3 and x = -2.1
2p = 4y - 12xy - 6x, 3q = 12 - 15y so 2p - 3q = 4y - 12xy - 6x - (12 - 15y) = 4y - 12xy - 6x - 12 + 15y = 19y -12xy - 6x - 12
(A) 3x + 2y = -2 (B) 6x - y = 6 (A) + 2(B): 3x + 2y + 12x - 2y = -2 + 12 or 15x = 10 or x = 2/3 substitute this value of x in (A) 2 + 2y = -2 2y = -4 and y = -2 Answer: x = 2/3, y = -2