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If the question is about y = 1-6x then (-5, 31) is in the solution set.
If that was not the equation, please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals".
-9x = 27 x = -3 The solution set contains only one value for x, -3, which is just a point on the number line 3 units to the left of zero.
x=2, 3, 4...
2x 4 10 is not an equation.
To find points of intersection of any functions, set them equal to each other: x4-2 = x2 x4-x2-2 = 0 factoring this yields: (x2-2)(x2+1)=0 by the zero identity, each of these factors can be set to zero to yield valid solutions: x2-2 = 0 x2 = 2 x = +/- sqrt(2) the second factor, when set equal to zero, yields an imaginary-valued solution. On a normal Cartesian coordinate plane, this means nothing. I assume you are only looking for points of intersection on a normal, real-valued Cartesian coordinate system (the normal x-y coordinate plane used in most elementary math classes). So, these two functions intersect at x = -sqrt(2) and x = sqrt(2)
the set of all values which, when substituted for unknowns, make an equation true. this is wrong
A coordinate pair is a set of two coordinates that plot the location on a Cartesian plane. The pair consists of the x-axis location followed by the y-axis location.
A set of 2 numbers is called an ordered pair
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
the set of numbers is called an ordered pair,
Not a coordinate but a pair (or larger set) of coordinates.These are ordered sets of numbers that give the distance of the point, from the origin, along each of the axes in multidimensional space.
This is most often called the "range" of the relation. * * * * * Though more often the first coordinate is the DOMAIN and the second coordinate is the RANGE.
the solution set
Any ordered pair that makes the set true
The point of the functional property is that for any pair in the set of ordered pairs, the first coordinate determines what the second one is. That's why you can write "G(x)" for any x in the domain ofG and not be ambiguous.
To construct a DFA that accepts the set of all strings of 0s and 1s with at most one pair of consecutive 0s and at most one pair of consecutive 1s, we can use the state diagram method. The DFA will have states to keep track of the number of consecutive 0s and 1s encountered so far. We can have states like q0, q1, q00, q11 to represent different scenarios. Transitions will move between states based on the input symbols. The final state will be one where the input string is accepted according to the given conditions.
That would be the "solution" to the set of equations.
By the substitution method By the elimination method By plotting them on a graph